Mechanical Models & Units

01Mechanical Models & Units

Models & Assumptions

Translate common modelling assumptions into their mathematical consequences.

Decide what the model includes

A mechanics model replaces a physical situation with objects, forces and equations. State the assumptions that make those equations valid, then interpret the solution in the original situation.

AssumptionConsequence
ParticleIgnore the object’s dimensions and rotation; represent its mass at one point.
Rigid rod or beamIts length and shape do not change; forces may act at different points.
Uniform rodMass is evenly distributed along its length, so its weight acts at its midpoint.
Light string or rodNeglect the connector’s mass.
Inextensible stringIts length stays fixed. When taut in a simple fixed-pulley system, the particles have equal speeds and acceleration magnitudes.
Smooth surfaceThere is no friction at that contact.
Smooth pulley with a light stringThe tension has the same magnitude on both sides.
Negligible air resistanceOmit air resistance as a force.
Constant gravityUse constant downward acceleration gg, normally 9.8 m s−29.8\,\mathrm{m\,s^{-2}} unless specified.

Interpret the formula in its setting

02Mechanical Models & Units

Scalars & Vectors

Distinguish magnitudes from quantities with direction and interpret signed components.

Does direction matter?

Scalars have a numerical value and no direction. In mechanics, mass, elapsed time, distance and speed are scalars.

Vectors have magnitude and direction. Displacement, velocity, acceleration and force are vectors.

On a line, choose one direction as positive. A negative velocity then means motion in the opposite direction. Speed is the magnitude of velocity, so it cannot be negative. Zero speed is possible; zero is not positive.

03Mechanical Models & Units

SI & Derived Units

Use metres, kilograms and seconds to construct the units of motion and force.

Keep a consistent unit system

The SI base units used most often here are the metre (m\mathrm m), kilogram (kg\mathrm{kg}) and second (s\mathrm s). A derived unit combines base units using the relationship between quantities.

QuantitySI unit and meaning
Displacement or distancem\mathrm m
Length
Velocity or speedm s−1\mathrm{m\,s^{-1}}
Length divided by time
Accelerationm s−2\mathrm{m\,s^{-2}}
Change in velocity divided by time
Force or weightN=kg m s−2\mathrm N=\mathrm{kg\,m\,s^{-2}}
Mass multiplied by acceleration
04Mechanical Models & Units

Unit Conversions

Convert base and compound units, including squared and cubed factors.

Convert each factor separately

Useful relationships are 1 km=1000 m1\,\mathrm{km}=1000\,\mathrm m, 1 m=100 cm1\,\mathrm m=100\,\mathrm{cm} and 1 cm=10 mm1\,\mathrm{cm}=10\,\mathrm{mm}. Also, 1 h=60 min=3600 s1\,\mathrm h=60\,\mathrm{min}=3600\,\mathrm s, 1 kg=1000 g1\,\mathrm{kg}=1000\,\mathrm g and 1 g=1000 mg1\,\mathrm g=1000\,\mathrm{mg}. If a unit is squared or cubed, apply the same power to its conversion factor. For unfamiliar units, such as feet or miles per hour, use the conversion factor supplied in the question.

05Mechanical Models & Units

Vectors in Mechanics

Combine components and calculate a vector’s magnitude, direction and bearing.

Work component by component

The perpendicular vectors i\mathbf i and j\mathbf j each have magnitude 11 and point along the chosen positive coordinate axes. For a vector q\mathbf q, q=xi+yj=(xy),∣q∣=x2+y2.\mathbf q=x\mathbf i+y\mathbf j=\begin{pmatrix}x\\y\end{pmatrix},\qquad |\mathbf q|=\sqrt{x^2+y^2}. Printed vectors are usually bold; in handwriting, underlining a letter identifies it as a vector. Add or subtract matching components. Multiplication by a scalar changes both components; a negative scalar reverses the direction. A head-to-tail sketch of vector addition gives the same resultant as adding the components.

NE43q
A vector with positive east and north components.

When i\mathbf i points east and j\mathbf j north, a bearing is measured clockwise from north. Sketch the signs of the components before finding an angle. The zero vector has magnitude zero and no unique direction.

For equilibrium, the resultant must be the zero vector. A force −R-\mathbf R cancels a resultant R\mathbf R component by component.

Show the component operations

Convert a magnitude and angle into components

Find a bearing outside the first quadrant

06Mechanical Models & Units

Types of Force

Recognise weight, normal reaction, tension, thrust and resistance in a force diagram.

Identify the interaction

A force has magnitude and direction and is measured in newtons. Mass is a scalar measured in kilograms; it describes the object’s inertia. Weight is the gravitational force on that mass. The same object keeps its mass when moved to a place with a different gg, but its weight mgmg changes.

ForceDirection and interpretation
Weight W=mgW=mgVertically downward in the usual near-Earth model.
Normal reaction RRPerpendicular to the contact surface, pushing on the object.
Tension TTAlong a taut string, pulling away from the object.
ThrustA compressive pushing force, for example from a rigid connector.
FrictionAlong the contact surface, opposing relative motion or the tendency to slide.
Air resistance or dragOpposes motion relative to the surrounding air.
Driving or applied forceUse the direction specified by the physical situation.
RmgTF
Forces on the block; arrows show force directions.

A block pulled to the right on a rough horizontal surface has weight downward, normal reaction upward, tension to the right and friction to the left. These are forces acting on the block; do not include forces the block exerts on its surroundings.

07Mechanical Models & Units

Limitations & Refinements

Explain how an assumption can fail and how a model could be improved.

Connect the criticism to the prediction

A model is useful only within the conditions where its assumptions are reasonable. Compare its predictions with the physical situation. A refinement adds an effect that was omitted or represents it more accurately.

SimplificationLimitation and refinement
Ignore air resistanceA falling object’s acceleration may reduce as its speed rises.
Refinement: Include a resistive force that depends on speed.
Smooth surfaceThe predicted acceleration may be too large if the real surface resists motion.
Refinement: Include friction or another resistance.
Light, inextensible stringA heavy or elastic connector may change the tension or motion.
Refinement: Allow for its mass or extension.
ParticleRotation, dimensions and contact positions cannot be studied.
Refinement: Use a rigid-body model when those effects matter.
Uniform objectIts centre of mass may not be at the geometric midpoint.
Refinement: Use the actual mass distribution or centre of mass.