SHM Systems & Energy

01SHM Systems & Energy

Mass-spring systems

This section covers the restoring force and time period of horizontal and vertical mass-spring simple harmonic oscillators.

Spring as a restoring system

When a mass attached to a spring is moved away from its equilibrium position and released, the spring can provide the restoring force required for simple harmonic motion.

For displacement xx from equilibrium, the restoring-force relationship is:

F=kx\boxed{F=-kx}

The minus sign shows that the force is directed opposite to the displacement and therefore back towards equilibrium.

Time period

For an oscillating mass mm attached to a spring with spring constant kk:

T=2πmk\boxed{T=2\pi\sqrt{\frac{m}{k}}}
Quantity Symbol Unit
Time period TT s\mathrm{s}
Oscillating mass mm kg\mathrm{kg}
Spring constant kk Nm1\mathrm{N\,m^{-1}}

This period relationship applies to both horizontal and vertical mass-spring arrangements. It does not contain gg, so changing the gravitational field strength does not change the period for the same values of mm and kk.

  • Increasing mm increases the period.
  • Increasing kk makes the spring stiffer and decreases the period.
  • The oscillation frequency is related to the period by f=1/Tf=1/T.

Worked example: For a mass-spring oscillator, m=2.0 kgm=2.0\ \mathrm{kg} and k=0.90 Nm1k=0.90\ \mathrm{N\,m^{-1}}. Determine its oscillation frequency.

Calculate the period first:

T=2πmkT=2\pi\sqrt{\frac{m}{k}}

T=2π2.00.90=9.37 sT=2\pi\sqrt{\frac{2.0}{0.90}}=9.37\ \mathrm{s}

Then use f=1/Tf=1/T:

f=19.37f=\frac{1}{9.37}

f=0.11 Hz\boxed{f=0.11\ \mathrm{Hz}}

Exam Tip: For a mass-spring period calculation, use the oscillating mass and the spring constant. Do not introduce gg into T=2πm/kT=2\pi\sqrt{m/k}.

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