Extending the Binomial Expansion

01Extending the Binomial Expansion

Negative & Fractional Powers

This section covers the general binomial expansion and its use with negative and fractional powers.

The general binomial expansion

The general binomial expansion extends the binomial theorem to negative and fractional powers. For a rational power nn and ∣x∣<1|x|\lt 1,

(1+x)n=1+nx+n(n−1)2!x2+n(n−1)(n−2)3!x3+⋯ .\begin{aligned} (1+x)^n={}&1+nx+\frac{n(n-1)}{2!}x^2\\ &+\frac{n(n-1)(n-2)}{3!}x^3+\cdots. \end{aligned}

Positive-integer powers give finite expansions. For negative or non-integer powers, the series continues indefinitely; questions usually require only its first few terms. The general formula is supplied in the formula booklet.

  • The coefficient factors decrease by 11: nn, then n−1n-1, then n−2n-2.
  • For (1+bx)n(1+bx)^n, replace every xx in the formula by the complete quantity bxbx, including its sign.
  • Retain the constant term when counting terms. Through x2x^2 means three terms; through x3x^3 means four.

A fractional power

For (1+x)1/2(1+x)^{1/2}, use n=12n=\frac12, so n−1=−12n-1=-\frac12 and n−2=−32n-2=-\frac32:

(1+x)1/2=1+12x+(12)(−12)2x2+(12)(−12)(−32)6x3+⋯=1+x2−x28+x316+⋯ ,∣x∣<1.\begin{aligned} (1+x)^{1/2}={}&1+\frac12x +\frac{(\frac12)(-\frac12)}{2}x^2\\ &+\frac{(\frac12)(-\frac12)(-\frac32)}{6}x^3+\cdots\\ ={}&1+\frac{x}{2}-\frac{x^2}{8}+\frac{x^3}{16}+\cdots, \qquad |x|\lt 1. \end{aligned}

A negative fractional power

A reciprocal square root combines both ideas: 11−x=(1−x)−1/2\dfrac1{\sqrt{1-x}}=(1-x)^{-1/2}. Substitute n=−12n=-\frac12 and replace xx by −x-x:

(1−x)−1/2=1+(−12)(−x)+(−12)(−32)2(−x)2+⋯=1+x2+3x28+⋯ ,∣x∣<1.\begin{aligned} (1-x)^{-1/2} &=1+\left(-\frac12\right)(-x) +\frac{(-\frac12)(-\frac32)}{2}(-x)^2+\cdots\\ &=1+\frac{x}{2}+\frac{3x^2}{8}+\cdots, \qquad |x|\lt 1. \end{aligned}

Exam Tip: Show the substituted coefficient factors before simplifying. Put negative signs and fractional powers in brackets so their effects remain clear.

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