Trigonometric Identities & Equations

01Trigonometric Identities & Equations

Trigonometric Identities

This section covers the two basic trigonometric identities, their origins and their use in rearranging equations.

The two basic identities

A trigonometric identity is an equality that holds for every angle for which its expressions are defined. The symbol ≡\equiv means “is identically equal to”. Remember that sin⁡2x\sin^2x means (sin⁡x)2(\sin x)^2.

tan⁡x≡sin⁡xcos⁡x,sin⁡2x+cos⁡2x≡1\tan x\equiv\frac{\sin x}{\cos x},\qquad \sin^2x+\cos^2x\equiv1

The tangent identity applies where cos⁡x≠0\cos x\ne0. Rearranging the second identity gives sin⁡2x≡1−cos⁡2x\sin^2x\equiv1-\cos^2x and cos⁡2x≡1−sin⁡2x\cos^2x\equiv1-\sin^2x. These substitutions let you replace mixed trigonometric terms with a single function.

Where the identities come from

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In this right-angled triangle, sin⁡θ=a/c\sin\theta=a/c, cos⁡θ=b/c\cos\theta=b/c and tan⁡θ=a/b\tan\theta=a/b. Dividing the first two ratios gives

sin⁡θcos⁡θ=a/cb/c=ab=tan⁡θ.\frac{\sin\theta}{\cos\theta}=\frac{a/c}{b/c}=\frac ab=\tan\theta.

Pythagoras gives a2+b2=c2a^2+b^2=c^2. Dividing by c2c^2 gives

(ac)2+(bc)2=1,\left(\frac ac\right)^2+\left(\frac bc\right)^2=1,

so sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1.

Worked example — rewrite an equation. Show that 3cos⁡x=2(1+sin⁡2x)3\cos x=2(1+\sin^2x) can be written as 2cos⁡2x+3cos⁡x−4=02\cos^2x+3\cos x-4=0.

Replace sin⁡2x\sin^2x by 1−cos⁡2x1-\cos^2x, then expand:

3cos⁡x=2(1+1−cos⁡2x)=4−2cos⁡2x.3\cos x=2\bigl(1+1-\cos^2x\bigr)=4-2\cos^2x.

Bring all terms to the same side:

2cos⁡2x+3cos⁡x−4=0.\boxed{2\cos^2x+3\cos x-4=0.}

Exam Tip: In a “show that” question, state the identity used and show the substitution and rearrangement. Writing only the final expression does not demonstrate the method.

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