Condensation Polymers

01Condensation Polymers

Condensation polymerisation

This section covers how bifunctional monomers form condensation polymers while eliminating small molecules.

How condensation polymers form

Condensation polymerisation forms long-chain molecules through repeated reactions between functional groups on monomers. Each monomer must be able to react at two positions so that the growing chain can continue reacting.

Formation of a new link normally eliminates a small molecule. Water is produced when carboxylic acids are used, while reactions involving acyl chlorides produce hydrogen chloride.

Monomers Polymer Link formed Small molecule
Dicarboxylic acid + diol Polyester Ester, COO\ce{-COO-} HX2O\ce{H2O}
Diacyl dichloride + diol Polyester Ester, COO\ce{-COO-} HCl\ce{HCl}
Dicarboxylic acid + diamine Polyamide Amide, CONH\ce{-CONH-} HX2O\ce{H2O}
Diacyl dichloride + diamine Polyamide Amide, CONH\ce{-CONH-} HCl\ce{HCl}

Reactive groups at both ends

1

Diol

Has two alcohol groups available for condensation.

HOROH\ce{HO-R-OH}
2

Dicarboxylic acid

Has two carboxylic acid groups.

HOOCRCOOH\ce{HOOC-R-COOH}
3

Diamine

Has two amine groups that can form amide links.

HX2NRNHX2\ce{H2N-R-NH2}

Carboxylic-acid routes to these links are reversible and require acid catalysis. Replacing the acid groups with more reactive acyl chloride groups makes the corresponding reactions proceed effectively to completion without that catalyst, although HCl\ce{HCl} is then released as a hazardous product.

Two different monomers are common, but one monomer can also form a condensation polymer when it contains both functional groups needed for repeated reaction.

  • A monomer containing both OH\ce{-OH} and COOH\ce{-COOH} groups can form a polyester.
  • An amino acid contains both an amine group and a carboxylic acid group and can form amide links by repeated condensation.

For a finite linear chain made from nn molecules of each of two bifunctional monomers, the 2n2n starting molecules become joined by 2n12n-1 new links. One reactive group remains at each chain end, so 2n12n-1 small molecules are lost.

Exam Tip: If a question asks for the polymer class, answer polyester or polyamide as appropriate. If it asks for the polymerisation process, state condensation polymerisation.

Create a free account to continue

Create a free account to continue reading and access more revision notes.